Remove base64 and URL decoding

This commit is contained in:
vvzvlad
2025-03-22 15:26:55 +03:00
parent 93698e0d4e
commit bbaf2314d5
2 changed files with 3 additions and 8 deletions
+3
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@@ -152,3 +152,6 @@ You can use any regex pattern, including:
The pattern is matched against the entire post text, so you can create complex filtering rules.
For some applications you will need to convert the request to an encoded URL:
```Салли.*и.*Фасолька|Увядший.*Лепесток``` -> ```%D0%A1%D0%B0%D0%BB%D0%BB%D0%B8.%2A%D0%B8. %2A%D0%A4%D0%B0%D1%81%D0%BE%D0%BB%D1%8C%D0%BA%D0%B0%7C%D0%A3%D0%B2%D1%8F%D0%B4%D1%88%D0%B8%D0%B9.%2A%D0%9B%D0%B5%D0%BF%D0%B5%D1%81%D1%82%D0%BE%D0%BA```
For example, you can use this tool: https://www.urlencoder.org/
-8
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@@ -587,14 +587,6 @@ async def get_rss_feed(channel: str,
#logger.info(f"valid_token: token {token}")
while True:
try:
if exclude_text: # Decode base64 parameters if they are encoded
try:
exclude_text = base64.b64decode(exclude_text.encode()).decode('utf-8') # Try to decode as base64 first
except Exception: # If base64 decoding fails, try URL decoding
try:
exclude_text = exclude_text.encode('latin1').decode('utf-8')
except UnicodeError:
pass # If all decoding fails, use original value
if output_type == 'rss':
rss_content = await generate_channel_rss(channel,